(9-x)^1/2+2=x-5

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Solution for (9-x)^1/2+2=x-5 equation: 


x in (-oo:+oo)

((9-x)^1)/2+2 = x-5 // - x-5

((9-x)^1)/2-x+2+5 = 0

(9-x)/2-x+2+5 = 0

(9-x)/2+(2*(-x))/2+(2^2)/2+(2*5)/2 = 0

2*(-x)-x+2*5+4+9 = 0

4-3*x+9+10 = 0

10-3*x+13 = 0

23-3*x = 0

(23-3*x)/2 = 0

(23-3*x)/2 = 0 // * 2

23-3*x = 0

23-3*x = 0 // - 23

-3*x = -23 // : -3

x = -23/(-3)

x = 23/3

x = 23/3

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